An object 3.0cm high is placed 60.0cm from a converging lens whose focal length is 20.0cm. Calculate the size of the image formed
- 0.5cm
-
1.5cm
- 2.0cm
- 6.0cm
The correct answer is: B
Explanation
F = \(\frac{UV}{U + V}\)20 = \(\frac{60 \times V}{60 + V}\)
V = 30cm
similarly, \(\frac{U}{V}\) = \(\frac{\text{height of object}}{\text{height of image}}\)
\(\frac{60}{30}\) = \(\frac{3}{h}\)
h = 1.5cm