A pool of water appears to be 1.0m deep when viewed vertically from above. If the refractive index of water is 1.33, what is the actual depth of the pool?
- 0.750m
- 1.013m
-
1.330m
- 13.3000m
The correct answer is: C
Explanation
n = \(\frac{\text {real depth}}{\text{apparent depth}}\)1.33 = \(\frac{\text {real depth}}{1}\)
real depth = 1.33cm