A 20-toothed gear wheel drives a 60-toothed one. If the angular speed of the smaller wheel is 120 rev s-1, the angular speed of the larger wheel is
- 3 rev s-1
- 40 rev s-1
-
360 rev s-1
- 2400 rev s-1
The correct answer is: C
Explanation
\(\frac{\text {speed of driver}}{\text {speeder driven}}\) = \(\frac{\text {no. of teeth of driver}}{\text {no. of teeth of driven}}\)\(\frac{120}{V}\) = \(\frac{20}{60}\)
v = 360 rev s-1