A force, 10N, drags a mass 10kg on a horizontal table with an acceleration of 0.2ms. If the acceleration due to gravity is 10ms-1, the coefficient of friction between the moving mass and the table is
- 0.02
-
0.08
- 0.20
- 0.80
The correct answer is: B
Explanation
\(\mu\)mg = ma
\(\mu\)mg = F - ma
\(\mu\) x 10 x 10 = 10 - (10 x 0.2)
100 \(\mu\) =10 - 2
dividing both sides by 100
\(\mu\) = 8 / 100
\(\mu\) = 0.08