A piano wire 0.5m long has a total mass of 0.01kg and is stretched with a tension of 800N. Calculate the frequency of the wire when it sounds its fundamental note
-
200Hz
- 100Hz
- 4Hz
- 2Hz
The correct answer is: A
Explanation
F = \(\frac{1}{2L}\)\(\sqrt\frac {T}{m}\)N:B m is mass per length
= \(\frac {0.01}{0.5}\)
= 0.02kgm-1
F = \(\frac{1}{2\times 0.5}\)\(\sqrt\frac {800}{0.02}\)
= 200Hz