An object is placed 10cm in front of a concave mirror of focal length 15cm. What is the position and nature of the image formed?
-
30cm and virtual
- 6cm and real
- 6cm and virtual
- 30cm and real
The correct answer is: A
Explanation
F = \(\frac{uv}{u + v}\)15 = \(\frac{10 \times v}{10 + v}\)
v = -30cm