A cell of internal resistance 2 ohms supplies current to a 6 ohms resistor. The efficiency of the cell is
- 12.0%
- 25.0%
- 33.3%
-
75.0%
The correct answer is: D
Explanation
Efficiency = \(\frac{IR}{I(R + r)}\) x 100= \(\frac{6}{I(2 + 6)}\) x 100
= 75%