A piece of wood of mass 40g and uniform cross-sectional area of 2cm2 floats upright in water. The length of the wood immersed is
- 30cm
- 40cm
-
20cm
- 2cm
The correct answer is: C
Explanation
Mw displaced = 40gdensity = \(\frac{mass}{\text{area x height}}\)
I = \(\frac{40}{2\times h}\)
h = 20cm