In a sound wave in air, the adjacent rarefactions and compressions are separated by a distance of 17cm. If the velocity of the sound wave is 340ms-1. Determine the frequency
- 10Hz
- 20Hz
-
1000Hz
- 5780Hz
The correct answer is: C
Explanation
\(\lambda\) = 2L2 x 17 = 34cm
F = \(\frac{V}{\lambda}\)
= \(\frac{340}{34 \times 10^{-2}}\)
= 1000Hz