The magnification of the image of an object placed in front of a convex mirror is \(\frac{1}{3}\). If the radius of curvature of the mirror is 24cm, what is the distance between its object and its image?
- 8cm
- 16cm
- 24cm
-
32cm
The correct answer is: D
Explanation
F = uv ; v = 1u12 = \(\frac{v + 3v}{v + 3v}\)
v = 16cm, u = 48cm
distance between U and V
= 48 - 16 =32cm