Three 2-µF capacitors are arranged as seen in the circuit above . The effective capacitance between E and F is
- 0.75µF
-
1.33µF
- 3.00µF
- 6.00µF
The correct answer is: B
Explanation
\(C_T = \frac{2 \times (2 + 2)}{2 + (2 + 2)}\)
= \(\frac{8}{6}\)
= 1.33 \(\mu\)F