The total power drawn from the cell in the circuit above is
- 12W
-
24W
- 32W
- 40W
The correct answer is: B
Explanation
Total resistance = resistance in series + resistance in parallel
= 4 + (\(\frac{4 \times 4}{4 + 4}\)) = 6\(\Omega\)
Total power drawn = \(\frac{V^2}{\text{R}}\) = \(\frac{12^2}{6}\) = 24W