1kg of copper is transferred quickly from boiling water to a block of ice. Calculate the mass of ice melted, neglecting heat loss. [specific heat capacity of copper 400Jkg-1K-1 and latent heat of fusion of ice 333 x 103Jkg-1]
- 60g
- 67g
-
120g
- 133g
The correct answer is: C
Explanation
Heat lost = heat gained1 x 400 x (100 - 0) = m x 333000
m = 0.12kg
converting to grams; 0.12 x 1000
= 120g