When a known standard resistor of 2\(\Omega\) is connected to the 0.0cm end of a meter bridge, the balance point is found to be at 55.0cm. What is the value of the unknown resistor?
- 1.10\(\Omega\)
-
1.64\(\Omega\)
- 2.44\(\Omega\)
- 27.50\(\Omega\)
The correct answer is: B
Explanation
\(\frac{R_1}{R_2}\) = \(\frac{L_1}{R_2}\)\(\frac{2}{R_2}\) = \(\frac{55}{45}\)
R = 1.64\(\Omega\)