A body of weight W N rest on a smooth plane inclined at an angle\(\theta\)o to the horizontal. What is the resolved part of the weight in Newtons along the plane?
-
W sin\(\theta\)
- W cos\(\theta\)
- W sec\(\theta\)
- W tan\(\theta\)
The correct answer is: A
Explanation
horizontal component = W cos(90o - \(\theta\))= W sin