A spring of force constant 1500Nm-1 is acted upon by a constant force of 75N. Calculate the potential energy stored in the string
-
1.9J
- 2.8J
- 3.45J
- 0.43J
The correct answer is: A
Explanation
P.E = \(\frac{1}{2}\)Fe= \(\frac{1}{2}\)\(\frac{F}{K}\)
= \(\frac{1}{2}\) x \(\frac{75 \times 75}{1500}\)
= 1.9J