A man hears his echo from a nearby hill 2s after he shouted. If the frequency of his voice is 260Hz and the wavelength is 1.29m, how far away is the hill?
- 330.0m
-
335.4m
- 660.0m
- 670.8m
The correct answer is: B
Explanation
v = \(\lambda\)F260 x 1.29 =335.4ms-1
Echo time = \(\frac{2}{2}\) = 1sec.
distance = v x t
= 335.4 x 1 = 335.4m