An equipment whose power is 1500W and resistance is 375 ohms would draw a current of
- 0.10A
-
2.00A
- 4.00A
- 77.5A
The correct answer is: B
Explanation
P = I2R \(\Rightarrow\) I = \(\sqrt\frac{P}{R}\)I = \(\sqrt\frac{1500}{375}\)
= 2A