How much heat is absorbed when a block of copper of mass 0.05kg and specific heat capacity 390Jkg-1K-1 is heated from 20oC to 70oC?
- 39 . 98 x 10-1J
-
9.75 x 102J
- 3.98 x 103J
- 9.75 x 103J
The correct answer is: B
Explanation
Q = mc\(\theta\)= 0.05 x 390 x (70 - 20)
= 975J