Which of the following apparatus will require the smallest fuse rating for its protection?
The correct answer is: A
Explanation
I = \(\frac{P}{V}\) = \(\frac{60}{240}\) = 0.25AI = \(\frac{P}{V}\) = \(\frac{60}{40}\) = 1.5A
I = \(\frac{P}{V}\) = \(\frac{40}{12}\) = 3.3A
I = \(\frac{P}{V}\) = \(\frac{40}{5}\) = 8A