An object of mass 400g and density 600kgm-3 is suspended with a sting so that half of it is immersed in paraffin of density 900kgm-3. The tension in the string is
- 1.0N
-
3.0N
- 4.0N
- 5.0N
The correct answer is: B
Explanation
volume of object = \(\frac{400 \times 10^{-2}}{600}\)= 0.00067m3
volume of paraffin displaced = \(\frac{1}{2}\) x 0.00067
= 0.00034m3
mass of paraffin = 900 x 34 x 10-5
= 0.3kg
weight of paraffin = 0.3 x 10
= 3N = upthrust = tension in the string