When the volume of a given mass of gas is halved and its temperature doubled, the pressure
- remains constant
-
increases by a factor of 4
- increases by a factor of 3
- decreases by a factor of 4
The correct answer is: B
Explanation
\(\frac{P_1V_1}{T_1}\) = \(\frac{P_2V_2}{T_2}\)V1 = 2V2 and T2 = 2T1
\(\frac{P_1\times 2V_2}{T_1}\) = \(\frac{P_2\times V_2}{2T_1}\)
P2 = 4P1