A parallel plate capacitor of area 10cm2 in vacuum has a capacitance of 10-2\(\mu\)F. What is the distance between the plates?(e = 9 x 10-12fm)
- 9 x 10-13m
-
9 x 10-7m
- 9 x 10-3m
- 9 x 107m
The correct answer is: B
Explanation
C = \(\frac {\varepsilon_o\ A}{d}\)10-2 x 10-6 = \(\frac {9 \times 10 ^{-12}}{d}\) x 10-4
= 9 x 10-7m