A 40-W instrument has a resistance of 90\(\Omega\). On what voltage should it be operated normally?
The correct answer is: A
Explanation
P = \(\frac{V}{R}\)V = \(\sqrt{PR}\)
V = \(\sqrt{40 \times 90}\)
= 60V
A 40-W instrument has a resistance of 90\(\Omega\). On what voltage should it be operated normally?