An object is projected with a velocity of 80ms-1 at an angle of 30o to the horizontal.The maximum height reached is
- 20m
-
80m
- 160m
- 320m
The correct answer is: B
Explanation
max. height = \(\frac{U^2\sin^2\theta}{2g}\)= \(\frac{80 \times 80 \times \sin^2(30)}{2 \times 10}\)
= 80m