A Motor Tyre is inflated to pressure of 2.0 x 105Nm-2 when the temperature of air is 27oC. What will be the pressure in it at 87oC assuming that the volume of the Tyre does not change?
- 2.6 x 105Nm-2
-
2.4 x 105Nm-2
- 2.2 x 105Nm-2
- 1.3 x 105Nm-2
The correct answer is: B
Explanation
\(\frac{p_1}{T_1}\) = \(\frac{p_2}{T_2}\)\(\frac{2 \times 10^5}{27 + 273}\) = \(\frac{p_2}{87 + 273}\)
P2 = 2.4 x 105Nm-2