The sound from a source travelled to the bottom of the sea and the echo was heard 4s later. If the speed of sound in sea water is 1500ms-1 the depth of the sea is
- 6000m
-
3000m
- 1500m
- 375m
The correct answer is: B
Explanation
t = 4s ; v = 150ms-1depth = X ; but 2X = vt
X = \(\frac {vt}{2}\) = \(\frac {1500 \times 4}{2}\)
X = 3000m