A pipe of length 45cm is closed at the end. Calculate the fundamental frequency of the sound wave generated in the pipe if the velocity of sound in air is 360ms-1 [Neglect end correction]
- 5.5Hz
- 148.5Hz
-
200.0Hz
- 550.0Hz
The correct answer is: C
Explanation
\(\lambda\) = 4L = 4 X 45 = 180cmF = \(\frac {V}{\lambda}\)
= \(\frac {360}{180 \times 10^{-2}}\)
= 200Hz