An object is placed in front of a converging lens of a focal length 20cm. The image is virtual and has a magnification of 2. What is the distance of the object from the lens?
- 5cm
-
10cm
- 30cm
- 40cm
The correct answer is: B
Explanation
V = -2uF = \(\frac{uv}{u + v}\)
20 = \(\frac{uv - 2u}{u - 2u}\)
u = 10cm