A capacitor 8\(\mu\)F is charged to a potential difference of 100V. The energy stored by the capacitor is
- 1.0 x 104J
- 8.0 x 10J
- 1.25 x 10J
-
4.0 x 10-2J
The correct answer is: D
Explanation
Energy = \(\frac{1}{2}\)CV2= \(\frac{1}{2}\) x 8 x 10-6 x (100)2
= 4 x 10-2J