A well-lagged bar of length 100cm has its ends maintained at 100oC and 40oC respectively. What is the temperature at a point 60cm from the hotter end?
- 58oC
- 62oC
- 64oC
-
76oC
The correct answer is: D
Explanation
100oC ....100cm60oC ....60cm
40oC .... 0cm
\(\frac{\theta - 40}{100 - 40}\) = \(\frac{60 - 0}{100 - 0}\)
\(\theta\) = 76oC