The primary winding of a transformer has 400 turns and its secondary has 100 turns. If a source of e.m.f. of 12V is applied to the primary, the secondary e.m.f. will be
-
3V
- 6V
- 24V
- 48V
The correct answer is: A
Explanation
\(\frac{V_s}{V_p}\) = \(\frac{N_s}{N_p}\) = \(\frac{I_p}{I_s}\)\(\frac{100}{400}\) = \(\frac{V_S}{12}\)
V = 3V