A uniform light beam XZ is Hinged at X and kept in equilibrium by the forces T and F as shown in the diagram above. if XO = 20cm and OY = 30cm, express T in terms of F
- T =2√3/3
- T= 2F
- T = 5V3F/3
-
T = 5F
The correct answer is: D
Explanation
Resolve T vertically and take a moment about x
T sin30º x 20 = 50 x F
T x 0.5 x 20 = 50F
T x 10 = 50F
T = \(\frac{50F}{10}\) = 5F