A ball is moving at 18ms\(^{-1}\) in a direction inclined at 60º to the horizontal. The horizontal component to its velocity is
- 9√3ms-1 ·
- 6√3ms-1 ·
- 8√3ms-1 ·
-
9ms-1 ·
The correct answer is: D
Explanation
Since the angle is inclined to the horizontal,
The horizontal component of the velocity V\(_x\) = V x cos \(\theta\) = 18 x cos 60º = 9m/s
(NOTE: Cos 60º = 0.5)