A parallel plate capacitor has a common plate area of 5 x 10\(^{-8}\)m2 and plate separation of 2 x 10\(^{-3}\)m, Assuming free space,
What is the capacitance? [\(\varepsilon\)o = 9.0 X 10-\(^{-12}\)C2N-1m-2]
- 2.25 x 10-17F
- 4.50 x 10-17F
-
2.25 x 10-16F
- 4.50 x 10-16F
The correct answer is: C
Explanation
C = \(\frac{{\varepsilon}_oA}{d}\)
= \(\frac{5{\times} 10^{-8} {\times} 10^{-12}{\times} 9}{2 {\times}10^{-3}}\)
= 2.25 x \(10^{-16}\)F