Electricity is supplied to a school along a cable of total resistance 0.5\(\Omega\) with the maximum current drawn from the mains as 100A. The maximum energy dissipated as heat for 1 hr is
- 3.6 x 103J
- 5.0 x 103J
- 3.0 x 105J
-
1.8 x 107J
The correct answer is: D
Explanation
Elect. energy = I2Rt= 100 x 100 x 0.5 x 3600
= 1.8 x 107J