Particles of mass 10\(^{-2}\)kg is fixed to the tip of a fan blade which rotates with angular velocity of 100rad-1. If the radius of the blade is 0.2m, the centripetal force is
- 2 N
-
20 N
- 200 N
- 400 N
The correct answer is: B
Explanation
Centripetal Force (F\(_c\)) = \(\frac{mv ^2}{r}\)
= \(mĪ^2r\)
(Since V = Īr)
F = 0.01 x \(100^2 \times 0.2 \)
F = 20 N