The equation of a wave traveling along the positive x-direction is given by;
y = 0.25 x 10\(^{-3}\) sin (500t – 0.025x).
Determine the angular frequency of the wave motion.
- 0.25 x 10-3rad s-1
- 0.25 x 10-1rad s-1
-
5.00 x 102rad s-1
- 2.50 x 103rad s-1
The correct answer is: C
Explanation
The general wave equation is given by;
y = A Sin(wt - 2πx/Wavelength)
where w = angular velocity
Thus comparing this equation with the equation
y = 0.25 x 10-3 Sin (500t - 0.025x)
That Amplitude = 0.25 x 10-3m
the angular velocity(w) = 500 (the coefficient of t in both equations)
∴ w = 500 rad s-1
= 5.00 x 102rad s-1