In the J-tube above, Y and X are on the same horizontal level and 30cm3 of air is trapped above Y when the atmospheric pressure is 75cm Hg, calculate the volume of air trapped above Y when 15cm Hg is now poured into the limb above X
- 15 cm3
-
25 cm3
- 35 cm3
- 45 cm3
The correct answer is: B
Explanation
∴ 75 x 30 = (75 + 15) x V2
75 x 30 = 90 x V2
| => V2 = | 75 x 30 |
| _90 |
| = | 2250 |
| _90 |
= 25cm2