A stream is flowing at 0.75ms\(^{-1}\) and a boat heading perpendicular for the stream landed at the opposite bank at an angle of 30Β°. Calculate the velocity of the boat.
The correct answer is: A
Explanation
Let the velocity of stream be Vs = 0.75m/s
Angle at which the boat lands ΞΈ = 30ΒΊ
the velocity of the boat = Vb
\(\frac{0.75}{V_b}\) = Sin30ΒΊ = 0.5
β΄ V\(_b\) = \(\frac{0.75}{0.5}\) = 1.5m/s
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