In the a.c circuit above, the current value is
- 0.58 A
- 3.00 A
-
4.00 A
- 6.67 A
The correct answer is: C
Explanation
Impedance Z = \(\sqrt{R^2 + X^2}\)
= \(\sqrt{(30)^2 + (40)^2}\)
∴ Z = \(\sqrt{2500}\) = 50\(\Omega\)
But current I = \(\frac{V}{Z}\) = \(\frac{200}{50}\) = 4.00 A
There is an explanation video available .