A gas with initial volume of 2 X 10\(^{-6}m^3\) is allowed to expand to six times its initial value at constant pressure of 2 x 10\(^5Nm^{-2}\). The work done is?
-
2.0J
- 4. 0 J
- 12.0 J
- 2.4 J
The correct answer is: A
Explanation
W = PĪV = 2 x 10\(^5\) * (12 x 10\(^{-6}\) - 2 x 10\(^{-6}\))
= 2 x 10\(^5\) 10 x 10\(^{-6}\)
= 2.0J
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