when a piece of rectangular glass block is inserted between two parallel capacitor,at constant plate area and distance of separation, the capacitance of the capacitor will
-
increase
- decrease
- decrease then increase
- remain constant
The correct answer is: A
Explanation
When you insert a dielectric material (like glass) between the plates, the permittivity ε increases because the dielectric constant k of glass is greater than that of air or vacuum. The new capacitance when a dielectric is inserted is given
C′ = \(\frac{\text{kεoA}}{\text{d}}\)
where k is the dielectric constant of the glass, and ε\(_0\) is the permittivity of free space.
Since k >1 for glass, inserting it increases the capacitance:
C ′ = kC
Thus, with the glass block inserted, the capacitance C′ will be greater than the original capacitance C.
There is an explanation video available .