the pressure of 3 moles of an ideal gas at a temperature of 27°C having a volume of 10-3m3 is
- 2.49 x 105-2
- 7.47 x 105-2
- 2.49 x 106-2
-
7.47 x 106-2
The correct answer is: D
Explanation
From the relation PV = nRTV = 10-33; n = 3 moles; T = 27 + 273 = 300k
R = 8.3 j mol-1 K-1
=> P = nRT/V = 3 X 8.3 X 300/10-3 = 7.47 X 106 Nm-2