A test tube of radius 1.0cm is loaded to 8.8g. If is placed upright in water, find the depth to which it would sink
-
2.8cm
- 5.2cm
- 25.5cm
- 28.0cm
The correct answer is: A
Explanation
Pressure = F/A = pgh, where p = density, h = depth and g = 10ms-2
But F = P x A
∴ Force exerted by the load test tube = cross-sectional Area x Pressure
i.e F = A x pgh
| ∴ h = | F_ |
| A x pg |
| = | mg |
| A x P x g |
| = | 8.8 x 10-3 x 10 |
| πr2 x p x g |
| = | _8.8 x 10-3 x 10 |
| π x (1.0-2)2 x 1000 x 10 |
= 0.028m or 2.8cm