The stylus of a phonograph record exerts a force of 7.7 x 10-2N on a groove of radius 10-5m. Compute the pressure exerted by the stylus on the groove
-
2.45 x 108 Nm-2
- 3.45 x 108 Nm-2
- 4.90 x 108 Nm-2
- 2.42 x 108 Nm-2
The correct answer is: A
Explanation
Pressure P = F/A Pressure P = \(\frac{F}{\pi r^2}\)
= \(\frac{7.7 \times 10^{-2}}{\pi \times 10^{-10}}\)
= 2.45 x 10\(10^8\)Nm\(^{-2}\)