An a.c circuit of e.m.f 12V has a resistor of resistance 8Ω connected in series to an inductor of inductive reactance 16Ω and a capacitor capacitive reactance 10Ω. The current flow in the circuit is
- 1.4A
-
1.2A
- 12.0A
- 14.0A
The correct answer is: B
Explanation
But z =
√ R2 + (XL - XC)2
=
√ 82 + (16 – 10) 2
=
√ 64 + 36
=
√ 100 = 10Ω
∴ Current (I) = V/Z = 12/10 = 1.2 A