The energy stored in an inductor of inductance 5mH when a current of 6A flows through it is
- 9.0 x 10-3J
-
9.0 x 10-2J
- 1.4 x 10-2J
- 1.8 x 10-3J
The correct answer is: B
Explanation
Energy stored in a coil of inductance, L, and carry a current, I is given byE = 1/2 L I2
= 1/2 x 5 x 10-3 x 6 x 6
= 9.0 x 10-2J