Given three capacitors 0.3μF, 0.5μF and 0.2μF, the joint capacitance when arranged to give minimum capacitance is
-
0.1μF
- 0.3μF
- 1.0μF
- 0.5μF
The correct answer is: A
Explanation
1/C = 1/0.3 + 1/0.5 + 1/0.2 = 10.3333=> C = 1 / 10.3333 = 0.09677
≅ 0.1μF
∴ C = 0.1μF