An electric device is rated 2000 W, 250 v. The correct fuse rating of the device is?
- 9 A
-
8 A
- 6 A
- 7 A
The correct answer is: B
Explanation
For the device rated 2000 W, 250 V, implies that current I, flowing is given by the relationPower = IV
I = (power)/v = (200)/250
= 8A.
∴ the most suitable fuse for the device is 8A